Base | Representation |
---|---|
bin | 1100001001001110000011… |
… | …0111101100111010101111 |
3 | 1202021111012211212121100122 |
4 | 3002103200313230322233 |
5 | 3222231440422214010 |
6 | 44222022412315155 |
7 | 2545455111204521 |
oct | 302234067547257 |
9 | 52244184777318 |
10 | 13352531054255 |
11 | 428885a753618 |
12 | 15b7987772abb |
13 | 75b1a4a39c83 |
14 | 3423a1aada11 |
15 | 1824e39ec855 |
hex | c24e0deceaf |
13352531054255 has 4 divisors (see below), whose sum is σ = 16023037265112. Its totient is φ = 10682024843400.
The previous prime is 13352531054227. The next prime is 13352531054263. The reversal of 13352531054255 is 55245013525331.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13352531054255 - 210 = 13352531053231 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1335253105421 + ... + 1335253105430.
It is an arithmetic number, because the mean of its divisors is an integer number (4005759316278).
Almost surely, 213352531054255 is an apocalyptic number.
13352531054255 is a deficient number, since it is larger than the sum of its proper divisors (2670506210857).
13352531054255 is an equidigital number, since it uses as much as digits as its factorization.
13352531054255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2670506210856.
The product of its (nonzero) digits is 1350000, while the sum is 44.
Adding to 13352531054255 its reverse (55245013525331), we get a palindrome (68597544579586).
The spelling of 13352531054255 in words is "thirteen trillion, three hundred fifty-two billion, five hundred thirty-one million, fifty-four thousand, two hundred fifty-five".
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