Base | Representation |
---|---|
bin | 1100001001001110000011… |
… | …0111111000010101001001 |
3 | 1202021111012211221222110222 |
4 | 3002103200313320111021 |
5 | 3222231440430213001 |
6 | 44222022413315425 |
7 | 2545455111461021 |
oct | 302234067702511 |
9 | 52244184858428 |
10 | 13352531101001 |
11 | 428885a785754 |
12 | 15b7987795b75 |
13 | 75b1a4a55331 |
14 | 3423a1ac2a81 |
15 | 1824e3a0b61b |
hex | c24e0df8549 |
13352531101001 has 4 divisors (see below), whose sum is σ = 13352622438912. Its totient is φ = 13352439763092.
The previous prime is 13352531100977. The next prime is 13352531101003. The reversal of 13352531101001 is 10010113525331.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13352531101001 - 238 = 13077653194057 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13352531101003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45449321 + ... + 45742166.
It is an arithmetic number, because the mean of its divisors is an integer number (3338155609728).
Almost surely, 213352531101001 is an apocalyptic number.
It is an amenable number.
13352531101001 is a deficient number, since it is larger than the sum of its proper divisors (91337911).
13352531101001 is an equidigital number, since it uses as much as digits as its factorization.
13352531101001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 91337910.
The product of its (nonzero) digits is 1350, while the sum is 26.
Adding to 13352531101001 its reverse (10010113525331), we get a palindrome (23362644626332).
The spelling of 13352531101001 in words is "thirteen trillion, three hundred fifty-two billion, five hundred thirty-one million, one hundred one thousand, one".
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