13353050453051 has 4 divisors (see below), whose sum is σ = 13353065650704. Its totient is φ = 13353035255400.

The previous prime is 13353050452981. The next prime is 13353050453111. The reversal of 13353050453051 is 15035405035331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13353050453051 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13353050452996 and 13353050453014.

It is not an unprimeable number, because it can be changed into a prime (13353050453251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6194360 + ... + 8066981.

It is an arithmetic number, because the mean of its divisors is an integer number (3338266412676).

Almost surely, 2^{13353050453051} is an apocalyptic number.

13353050453051 is a deficient number, since it is larger than the sum of its proper divisors (15197653).

13353050453051 is an equidigital number, since it uses as much as digits as its factorization.

13353050453051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15197652.

The product of its (nonzero) digits is 202500, while the sum is 38.

Adding to 13353050453051 its reverse (15035405035331), we get a palindrome (28388455488382).

The spelling of 13353050453051 in words is "thirteen trillion, three hundred fifty-three billion, fifty million, four hundred fifty-three thousand, fifty-one".