Base | Representation |
---|---|
bin | 11110010111001000111100… |
… | …010110000101101100100111 |
3 | 122111210111021000012122101220 |
4 | 132113020330112011230213 |
5 | 120000240101141443403 |
6 | 1151555313433351423 |
7 | 40061223116405130 |
oct | 3627107426055447 |
9 | 574714230178356 |
10 | 133531545656103 |
11 | 396024573a9771 |
12 | 12b87384568573 |
13 | 5967c808b434a |
14 | 24d8d65b0cc87 |
15 | 10686de0b1953 |
hex | 79723c585b27 |
133531545656103 has 128 divisors (see below), whose sum is σ = 219039311462400. Its totient is φ = 70721700134400.
The previous prime is 133531545656053. The next prime is 133531545656141. The reversal of 133531545656103 is 301656545135331.
It is not a de Polignac number, because 133531545656103 - 225 = 133531512101671 is a prime.
It is a super-2 number, since 2×1335315456561032 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133531545656603) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 1433756848 + ... + 1433849978.
It is an arithmetic number, because the mean of its divisors is an integer number (1711244620800).
Almost surely, 2133531545656103 is an apocalyptic number.
133531545656103 is a deficient number, since it is larger than the sum of its proper divisors (85507765806297).
133531545656103 is a wasteful number, since it uses less digits than its factorization.
133531545656103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 93813.
The product of its (nonzero) digits is 7290000, while the sum is 51.
The spelling of 133531545656103 in words is "one hundred thirty-three trillion, five hundred thirty-one billion, five hundred forty-five million, six hundred fifty-six thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •