Base | Representation |
---|---|
bin | 1100001001010000011110… |
… | …1000001001110100010001 |
3 | 1202021112220011101222202120 |
4 | 3002110013220021310101 |
5 | 3222234303402232440 |
6 | 44222211121204453 |
7 | 2545510165132023 |
oct | 302240750116421 |
9 | 52245804358676 |
10 | 13353181289745 |
11 | 42890637a3120 |
12 | 15b7b29490729 |
13 | 75b2796741bb |
14 | 3424241b2013 |
15 | 182530b3edd0 |
hex | c2507a09d11 |
13353181289745 has 64 divisors (see below), whose sum is σ = 23440302858240. Its totient is φ = 6437352627200.
The previous prime is 13353181289743. The next prime is 13353181289801. The reversal of 13353181289745 is 54798218135331.
It is not a de Polignac number, because 13353181289745 - 21 = 13353181289743 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13353181289743) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 320345305 + ... + 320386985.
It is an arithmetic number, because the mean of its divisors is an integer number (366254732160).
Almost surely, 213353181289745 is an apocalyptic number.
13353181289745 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13353181289745 is a deficient number, since it is larger than the sum of its proper divisors (10087121568495).
13353181289745 is a wasteful number, since it uses less digits than its factorization.
13353181289745 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 52726.
The product of its digits is 21772800, while the sum is 60.
The spelling of 13353181289745 in words is "thirteen trillion, three hundred fifty-three billion, one hundred eighty-one million, two hundred eighty-nine thousand, seven hundred forty-five".
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