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133533550021345 = 596233052990907
BaseRepresentation
bin11110010111001010110011…
…110100001000101011100001
3122111210200102200202221121121
4132113022303310020223201
5120000303202301140340
61152000244354052241
740061323565260435
oct3627126364105341
9574720380687547
10133533550021345
1139603295857a71
1212b8784387a081
13596820cc29596
1424d90b5dc29c5
1510687aa03794a
hex7972b3d08ae1

133533550021345 has 16 divisors (see below), whose sum is σ = 160263924082560. Its totient is φ = 106811065027584.

The previous prime is 133533550021343. The next prime is 133533550021357. The reversal of 133533550021345 is 543120055335331.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 133533550021345 - 21 = 133533550021343 is a prime.

It is not an unprimeable number, because it can be changed into a prime (133533550021343) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1468857382 + ... + 1468948288.

It is an arithmetic number, because the mean of its divisors is an integer number (10016495255160).

Almost surely, 2133533550021345 is an apocalyptic number.

It is an amenable number.

133533550021345 is a deficient number, since it is larger than the sum of its proper divisors (26730374061215).

133533550021345 is an equidigital number, since it uses as much as digits as its factorization.

133533550021345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 131064.

The product of its (nonzero) digits is 1215000, while the sum is 43.

The spelling of 133533550021345 in words is "one hundred thirty-three trillion, five hundred thirty-three billion, five hundred fifty million, twenty-one thousand, three hundred forty-five".

Divisors: 1 5 9623 30529 48115 90907 152645 454535 293780567 874798061 1468902835 2775299803 4373990305 13876499015 26706710004269 133533550021345