Base | Representation |
---|---|
bin | 1100001001010001101111… |
… | …1000001000010001100111 |
3 | 1202021120202211200011212201 |
4 | 3002110123320020101213 |
5 | 3222241002340201210 |
6 | 44222304534555331 |
7 | 2545521461613154 |
oct | 302243370102147 |
9 | 52246684604781 |
10 | 13353521022055 |
11 | 4289218545025 |
12 | 15b8003208b47 |
13 | 75b301b73a36 |
14 | 34245736922b |
15 | 18255089b53a |
hex | c251be08467 |
13353521022055 has 4 divisors (see below), whose sum is σ = 16024225226472. Its totient is φ = 10682816817640.
The previous prime is 13353521022001. The next prime is 13353521022067. The reversal of 13353521022055 is 55022012535331.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13353521022055 - 27 = 13353521021927 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1335352102201 + ... + 1335352102210.
It is an arithmetic number, because the mean of its divisors is an integer number (4006056306618).
Almost surely, 213353521022055 is an apocalyptic number.
13353521022055 is a deficient number, since it is larger than the sum of its proper divisors (2670704204417).
13353521022055 is an equidigital number, since it uses as much as digits as its factorization.
13353521022055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2670704204416.
The product of its (nonzero) digits is 135000, while the sum is 37.
Adding to 13353521022055 its reverse (55022012535331), we get a palindrome (68375533557386).
The spelling of 13353521022055 in words is "thirteen trillion, three hundred fifty-three billion, five hundred twenty-one million, twenty-two thousand, fifty-five".
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