13354000453351 has 4 divisors (see below), whose sum is σ = 13373725713192. Its totient is φ = 13334275193512.

The previous prime is 13354000453333. The next prime is 13354000453369. The reversal of 13354000453351 is 15335400045331.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13354000453333) and next prime (13354000453369).

It is a cyclic number.

It is not a de Polignac number, because 13354000453351 - 2⁵ = 13354000453319 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13354000453351.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13354000453751) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9862628905 + ... + 9862630258.

It is an arithmetic number, because the mean of its divisors is an integer number (3343431428298).

Almost surely, 2^{13354000453351} is an apocalyptic number.

13354000453351 is a deficient number, since it is larger than the sum of its proper divisors (19725259841).

13354000453351 is an equidigital number, since it uses as much as digits as its factorization.

13354000453351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19725259840.

The product of its (nonzero) digits is 162000, while the sum is 37.

Adding to 13354000453351 its reverse (15335400045331), we get a palindrome (28689400498682).

The spelling of 13354000453351 in words is "thirteen trillion, three hundred fifty-four billion, four hundred fifty-three thousand, three hundred fifty-one".