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13354045331 = 112110364011
BaseRepresentation
bin11000110111111011…
…01000111110010011
31021110122222210100112
430123331220332103
5204322113422311
610045035311535
7651632340524
oct143375507623
937418883315
1013354045331
115733012a00
1227082ab5ab
13134a843293
149097aa84b
1553258928b
hex31bf68f93

13354045331 has 6 divisors (see below), whose sum is σ = 14678413596. Its totient is φ = 12140041100.

The previous prime is 13354045277. The next prime is 13354045337.

13354045331 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 13354045331 - 210 = 13354044307 is a prime.

It is a super-2 number, since 2×133540453312 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13354045337) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 55181885 + ... + 55182126.

It is an arithmetic number, because the mean of its divisors is an integer number (2446402266).

Almost surely, 213354045331 is an apocalyptic number.

13354045331 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13354045331 is a deficient number, since it is larger than the sum of its proper divisors (1324368265).

13354045331 is a wasteful number, since it uses less digits than its factorization.

13354045331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 110364033 (or 110364022 counting only the distinct ones).

The product of its (nonzero) digits is 32400, while the sum is 32.

It can be divided in two parts, 133540 and 45331, that added together give a palindrome (178871).

The spelling of 13354045331 in words is "thirteen billion, three hundred fifty-four million, forty-five thousand, three hundred thirty-one".

Divisors: 1 11 121 110364011 1214004121 13354045331