13354111404545 has 4 divisors (see below), whose sum is σ = 16024933685460. Its totient is φ = 10683289123632.

The previous prime is 13354111404509. The next prime is 13354111404593. The reversal of 13354111404545 is 54540411145331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2495300441104 + 10858810963441 = 1579652^2 + 3295271^2 .

It is a cyclic number.

It is not a de Polignac number, because 13354111404545 - 2¹⁴ = 13354111388161 is a prime.

It is a super-3 number, since 3×13354111404545³ (a number of 40 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1335411140450 + ... + 1335411140459.

It is an arithmetic number, because the mean of its divisors is an integer number (4006233421365).

Almost surely, 2^{13354111404545} is an apocalyptic number.

It is an amenable number.

13354111404545 is a deficient number, since it is larger than the sum of its proper divisors (2670822280915).

13354111404545 is an equidigital number, since it uses as much as digits as its factorization.

13354111404545 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2670822280914.

The product of its (nonzero) digits is 288000, while the sum is 41.

Adding to 13354111404545 its reverse (54540411145331), we get a palindrome (67894522549876).

The spelling of 13354111404545 in words is "thirteen trillion, three hundred fifty-four billion, one hundred eleven million, four hundred four thousand, five hundred forty-five".