Base | Representation |
---|---|
bin | 1100001001010011111100… |
… | …0100010000101000000000 |
3 | 1202021122021222120201101211 |
4 | 3002110333010100220000 |
5 | 3222243210004421134 |
6 | 44222443304535504 |
7 | 2545542221025001 |
oct | 302247704205000 |
9 | 52248258521354 |
10 | 13354111404544 |
11 | 42894a0824139 |
12 | 15b8148a81594 |
13 | 75b397282ba1 |
14 | 3424b192b1a8 |
15 | 182587619764 |
hex | c253f110a00 |
13354111404544 has 40 divisors (see below), whose sum is σ = 27842233652640. Its totient is φ = 6386748926976.
The previous prime is 13354111404509. The next prime is 13354111404593. The reversal of 13354111404544 is 44540411145331.
It is a junction number, because it is equal to n+sod(n) for n = 13354111404497 and 13354111404506.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 566993634 + ... + 567017185.
It is an arithmetic number, because the mean of its divisors is an integer number (696055841316).
Almost surely, 213354111404544 is an apocalyptic number.
It is an amenable number.
13354111404544 is an abundant number, since it is smaller than the sum of its proper divisors (14488122248096).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13354111404544 is an equidigital number, since it uses as much as digits as its factorization.
13354111404544 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1134010860 (or 1134010844 counting only the distinct ones).
The product of its (nonzero) digits is 230400, while the sum is 40.
Adding to 13354111404544 its reverse (44540411145331), we get a palindrome (57894522549875).
The spelling of 13354111404544 in words is "thirteen trillion, three hundred fifty-four billion, one hundred eleven million, four hundred four thousand, five hundred forty-four".
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