Base | Representation |
---|---|
bin | 100111110011001… |
… | …1010110011110001 |
3 | 10110001220222021200 |
4 | 1033212122303301 |
5 | 10213340040340 |
6 | 340303441413 |
7 | 45044214315 |
oct | 11746326361 |
9 | 3401828250 |
10 | 1335471345 |
11 | 62592542a |
12 | 3132b6269 |
13 | 1838a7440 |
14 | c9515b45 |
15 | 7c39a330 |
hex | 4f99acf1 |
1335471345 has 48 divisors (see below), whose sum is σ = 2496351312. Its totient is φ = 656547840.
The previous prime is 1335471343. The next prime is 1335471383. The reversal of 1335471345 is 5431745331.
It can be written as a sum of positive squares in 8 ways, for example, as 241118784 + 1094352561 = 15528^2 + 33081^2 .
It is not a de Polignac number, because 1335471345 - 21 = 1335471343 is a prime.
It is a super-2 number, since 2×13354713452 = 3566967426632218050, which contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1335471341) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 640705 + ... + 642785.
It is an arithmetic number, because the mean of its divisors is an integer number (52007319).
Almost surely, 21335471345 is an apocalyptic number.
1335471345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1335471345 is a deficient number, since it is larger than the sum of its proper divisors (1160879967).
1335471345 is a wasteful number, since it uses less digits than its factorization.
1335471345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3202 (or 3199 counting only the distinct ones).
The product of its digits is 75600, while the sum is 36.
The square root of 1335471345 is about 36544.1013708095. The cubic root of 1335471345 is about 1101.2303987135.
The spelling of 1335471345 in words is "one billion, three hundred thirty-five million, four hundred seventy-one thousand, three hundred forty-five".
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