Base | Representation |
---|---|
bin | 1100001001011000000000… |
… | …0001010001101000111001 |
3 | 1202021202002221010002012121 |
4 | 3002112000001101220321 |
5 | 3222302422443010210 |
6 | 44223143353441241 |
7 | 2545611222444052 |
oct | 302260001215071 |
9 | 52252087102177 |
10 | 13355201141305 |
11 | 42899aa969531 |
12 | 15b83b1a10221 |
13 | 75b50bc7c23a |
14 | 342576557729 |
15 | 1825ed1246da |
hex | c2580051a39 |
13355201141305 has 8 divisors (see below), whose sum is σ = 16026567408000. Its totient is φ = 10683943554096.
The previous prime is 13355201141291. The next prime is 13355201141339. The reversal of 13355201141305 is 50314110255331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13355201141305 - 211 = 13355201139257 is a prime.
It is a super-2 number, since 2×133552011413052 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26899275 + ... + 27391264.
It is an arithmetic number, because the mean of its divisors is an integer number (2003320926000).
Almost surely, 213355201141305 is an apocalyptic number.
It is an amenable number.
13355201141305 is a deficient number, since it is larger than the sum of its proper divisors (2671366266695).
13355201141305 is an equidigital number, since it uses as much as digits as its factorization.
13355201141305 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 54339743.
The product of its (nonzero) digits is 27000, while the sum is 34.
Adding to 13355201141305 its reverse (50314110255331), we get a palindrome (63669311396636).
The spelling of 13355201141305 in words is "thirteen trillion, three hundred fifty-five billion, two hundred one million, one hundred forty-one thousand, three hundred five".
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