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13355201141305 = 54919954290539
BaseRepresentation
bin1100001001011000000000…
…0001010001101000111001
31202021202002221010002012121
43002112000001101220321
53222302422443010210
644223143353441241
72545611222444052
oct302260001215071
952252087102177
1013355201141305
1142899aa969531
1215b83b1a10221
1375b50bc7c23a
14342576557729
151825ed1246da
hexc2580051a39

13355201141305 has 8 divisors (see below), whose sum is σ = 16026567408000. Its totient is φ = 10683943554096.

The previous prime is 13355201141291. The next prime is 13355201141339. The reversal of 13355201141305 is 50314110255331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13355201141305 - 211 = 13355201139257 is a prime.

It is a super-2 number, since 2×133552011413052 (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26899275 + ... + 27391264.

It is an arithmetic number, because the mean of its divisors is an integer number (2003320926000).

Almost surely, 213355201141305 is an apocalyptic number.

It is an amenable number.

13355201141305 is a deficient number, since it is larger than the sum of its proper divisors (2671366266695).

13355201141305 is an equidigital number, since it uses as much as digits as its factorization.

13355201141305 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 54339743.

The product of its (nonzero) digits is 27000, while the sum is 34.

Adding to 13355201141305 its reverse (50314110255331), we get a palindrome (63669311396636).

The spelling of 13355201141305 in words is "thirteen trillion, three hundred fifty-five billion, two hundred one million, one hundred forty-one thousand, three hundred five".

Divisors: 1 5 49199 245995 54290539 271452695 2671040228261 13355201141305