Base | Representation |
---|---|
bin | 10011011011110011110… |
… | …111010101110001011001 |
3 | 11201200020110122001221111 |
4 | 103123303313111301121 |
5 | 133340131443413340 |
6 | 2501311245140321 |
7 | 165326465112142 |
oct | 23336367256131 |
9 | 4650213561844 |
10 | 1335531232345 |
11 | 475439621a22 |
12 | 196a0285a6a1 |
13 | 98c2b3ba08b |
14 | 488d645aac9 |
15 | 24b1843caea |
hex | 136f3dd5c59 |
1335531232345 has 16 divisors (see below), whose sum is σ = 1636780128768. Its totient is φ = 1045664441280.
The previous prime is 1335531232331. The next prime is 1335531232361. The reversal of 1335531232345 is 5432321355331.
It is a de Polignac number, because none of the positive numbers 2k-1335531232345 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1335531232298 and 1335531232307.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15051460 + ... + 15139930.
It is an arithmetic number, because the mean of its divisors is an integer number (102298758048).
Almost surely, 21335531232345 is an apocalyptic number.
It is an amenable number.
1335531232345 is a deficient number, since it is larger than the sum of its proper divisors (301248896423).
1335531232345 is an equidigital number, since it uses as much as digits as its factorization.
1335531232345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 152760.
The product of its digits is 486000, while the sum is 40.
Adding to 1335531232345 its reverse (5432321355331), we get a palindrome (6767852587676).
The spelling of 1335531232345 in words is "one trillion, three hundred thirty-five billion, five hundred thirty-one million, two hundred thirty-two thousand, three hundred forty-five".
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