Base | Representation |
---|---|
bin | 11110010111011101001010… |
… | …001001011010010111100010 |
3 | 122111212120021202121201120111 |
4 | 132113131022021122113202 |
5 | 120001114030011103102 |
6 | 1152013303401001534 |
7 | 40062622041615412 |
oct | 3627351211322742 |
9 | 574776252551514 |
10 | 133553252050402 |
11 | 39610686069008 |
12 | 12b8b621a832aa |
13 | 596a02c966b42 |
14 | 24da0248a2642 |
15 | 106905ea45cd7 |
hex | 79774a25a5e2 |
133553252050402 has 4 divisors (see below), whose sum is σ = 200329878075606. Its totient is φ = 66776626025200.
The previous prime is 133553252050331. The next prime is 133553252050433. The reversal of 133553252050402 is 204050252355331.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 109852430064601 + 23700821985801 = 10481051^2 + 4868349^2 .
It is a super-2 number, since 2×1335532520504022 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33388313012599 + ... + 33388313012602.
Almost surely, 2133553252050402 is an apocalyptic number.
133553252050402 is a deficient number, since it is larger than the sum of its proper divisors (66776626025204).
133553252050402 is an equidigital number, since it uses as much as digits as its factorization.
133553252050402 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66776626025203.
The product of its (nonzero) digits is 540000, while the sum is 40.
The spelling of 133553252050402 in words is "one hundred thirty-three trillion, five hundred fifty-three billion, two hundred fifty-two million, fifty thousand, four hundred two".
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