13355440411333 has 4 divisors (see below), whose sum is σ = 13815972839340. Its totient is φ = 12894907983328.

The previous prime is 13355440411283. The next prime is 13355440411363. The reversal of 13355440411333 is 33311404455331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10962237599329 + 2393202812004 = 3310927^2 + 1546998^2 .

It is a cyclic number.

It is not a de Polignac number, because 13355440411333 - 2²⁹ = 13354903540421 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13355440411363) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 230266213960 + ... + 230266214017.

It is an arithmetic number, because the mean of its divisors is an integer number (3453993209835).

Almost surely, 2^{13355440411333} is an apocalyptic number.

It is an amenable number.

13355440411333 is a deficient number, since it is larger than the sum of its proper divisors (460532428007).

13355440411333 is an equidigital number, since it uses as much as digits as its factorization.

13355440411333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 460532428006.

The product of its (nonzero) digits is 388800, while the sum is 40.

Adding to 13355440411333 its reverse (33311404455331), we get a palindrome (46666844866664).

The spelling of 13355440411333 in words is "thirteen trillion, three hundred fifty-five billion, four hundred forty million, four hundred eleven thousand, three hundred thirty-three".