Search a number
-
+
133564714211 = 883151262417
BaseRepresentation
bin111110001100100010…
…0111100110011100011
3110202202100120111020002
41330121010330303203
54142020031323321
6141205255210215
712435600224105
oct1743104746343
9422670514202
10133564714211
115170a887735
1221a7667696b
13c79757ba96
146670ab1575
15371aca520b
hex1f1913cce3

133564714211 has 4 divisors (see below), whose sum is σ = 133715977512. Its totient is φ = 133413450912.

The previous prime is 133564714207. The next prime is 133564714223. The reversal of 133564714211 is 112417465331.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 112417465331 = 319135229541.

It is a cyclic number.

It is not a de Polignac number, because 133564714211 - 22 = 133564714207 is a prime.

It is a super-3 number, since 3×1335647142113 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133564714271) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75630326 + ... + 75632091.

It is an arithmetic number, because the mean of its divisors is an integer number (33428994378).

Almost surely, 2133564714211 is an apocalyptic number.

133564714211 is a deficient number, since it is larger than the sum of its proper divisors (151263301).

133564714211 is an equidigital number, since it uses as much as digits as its factorization.

133564714211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 151263300.

The product of its digits is 60480, while the sum is 38.

The spelling of 133564714211 in words is "one hundred thirty-three billion, five hundred sixty-four million, seven hundred fourteen thousand, two hundred eleven".

Divisors: 1 883 151262417 133564714211