Base | Representation |
---|---|
bin | 11110011000001001110100… |
… | …111101100010111001000111 |
3 | 122112001011002101101000120011 |
4 | 132120021310331202321013 |
5 | 120002410242020001020 |
6 | 1152051314553251051 |
7 | 40066240440145201 |
oct | 3630116475427107 |
9 | 575034071330504 |
10 | 133601215000135 |
11 | 39629a58989043 |
12 | 12b98988703a87 |
13 | 597170468947c |
14 | 24dc494851771 |
15 | 106a41a65a35a |
hex | 798274f62e47 |
133601215000135 has 4 divisors (see below), whose sum is σ = 160321458000168. Its totient is φ = 106880972000104.
The previous prime is 133601215000111. The next prime is 133601215000163. The reversal of 133601215000135 is 531000512106331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 133601215000135 - 25 = 133601215000103 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 133601215000097 and 133601215000106.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13360121500009 + ... + 13360121500018.
It is an arithmetic number, because the mean of its divisors is an integer number (40080364500042).
Almost surely, 2133601215000135 is an apocalyptic number.
133601215000135 is a deficient number, since it is larger than the sum of its proper divisors (26720243000033).
133601215000135 is an equidigital number, since it uses as much as digits as its factorization.
133601215000135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26720243000032.
The product of its (nonzero) digits is 8100, while the sum is 31.
Adding to 133601215000135 its reverse (531000512106331), we get a palindrome (664601727106466).
The spelling of 133601215000135 in words is "one hundred thirty-three trillion, six hundred one billion, two hundred fifteen million, one hundred thirty-five", and thus it is an aban number.
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