Base | Representation |
---|---|
bin | 111110001110000000… |
… | …1000011110100100111 |
3 | 110202212210100210022111 |
4 | 1330130001003310213 |
5 | 4142120142313043 |
6 | 141214220141451 |
7 | 12440036324242 |
oct | 1743401036447 |
9 | 422783323274 |
10 | 133614026023 |
11 | 517356a83a5 |
12 | 21a8b097887 |
13 | c7a4855b7a |
14 | 667746a259 |
15 | 372029609d |
hex | 1f1c043d27 |
133614026023 has 4 divisors (see below), whose sum is σ = 133645520728. Its totient is φ = 133582531320.
The previous prime is 133614026011. The next prime is 133614026053. The reversal of 133614026023 is 320620416331.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 320620416331 = 211153 ⋅1518427.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133614026023 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133614026053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15740988 + ... + 15749473.
It is an arithmetic number, because the mean of its divisors is an integer number (33411380182).
Almost surely, 2133614026023 is an apocalyptic number.
133614026023 is a deficient number, since it is larger than the sum of its proper divisors (31494705).
133614026023 is an equidigital number, since it uses as much as digits as its factorization.
133614026023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31494704.
The product of its (nonzero) digits is 15552, while the sum is 31.
The spelling of 133614026023 in words is "one hundred thirty-three billion, six hundred fourteen million, twenty-six thousand, twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •