Base | Representation |
---|---|
bin | 111110001110000100… |
… | …0100101111110110111 |
3 | 110202212221002010101222 |
4 | 1330130020211332313 |
5 | 4142121144012301 |
6 | 141214330340555 |
7 | 12440062161116 |
oct | 1743410457667 |
9 | 422787063358 |
10 | 133616000951 |
11 | 51736827174 |
12 | 21a8b88a75b |
13 | c7a5097a74 |
14 | 6677821c7d |
15 | 372053631b |
hex | 1f1c225fb7 |
133616000951 has 4 divisors (see below), whose sum is σ = 134072028552. Its totient is φ = 133159973352.
The previous prime is 133616000941. The next prime is 133616000977. The reversal of 133616000951 is 159000616331.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 159000616331 = 89 ⋅1786523779.
It is a cyclic number.
It is not a de Polignac number, because 133616000951 - 210 = 133615999927 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133616000941) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 228013361 + ... + 228013946.
It is an arithmetic number, because the mean of its divisors is an integer number (33518007138).
Almost surely, 2133616000951 is an apocalyptic number.
133616000951 is a deficient number, since it is larger than the sum of its proper divisors (456027601).
133616000951 is an equidigital number, since it uses as much as digits as its factorization.
133616000951 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 456027600.
The product of its (nonzero) digits is 14580, while the sum is 35.
The spelling of 133616000951 in words is "one hundred thirty-three billion, six hundred sixteen million, nine hundred fifty-one", and thus it is an aban number.
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