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13362171981 = 34454057327
BaseRepresentation
bin11000111000111001…
…01001000001001101
31021111020021200000120
430130130221001031
5204331204000411
610045525415153
7652061405424
oct143434510115
937436250016
1013362171981
115737663644
12270ab6a4b9
13134c42a252
1490a8c42bb
15533142106
hex31c72904d

13362171981 has 4 divisors (see below), whose sum is σ = 17816229312. Its totient is φ = 8908114652.

The previous prime is 13362171961. The next prime is 13362171997. The reversal of 13362171981 is 18917126331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13362171981 - 210 = 13362170957 is a prime.

It is a super-2 number, since 2×133621719812 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13362171941) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2227028661 + ... + 2227028666.

It is an arithmetic number, because the mean of its divisors is an integer number (4454057328).

Almost surely, 213362171981 is an apocalyptic number.

It is an amenable number.

13362171981 is a deficient number, since it is larger than the sum of its proper divisors (4454057331).

13362171981 is an equidigital number, since it uses as much as digits as its factorization.

13362171981 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4454057330.

The product of its digits is 54432, while the sum is 42.

The spelling of 13362171981 in words is "thirteen billion, three hundred sixty-two million, one hundred seventy-one thousand, nine hundred eighty-one".

Divisors: 1 3 4454057327 13362171981