Base | Representation |
---|---|
bin | 11110011000100100110111… |
… | …000100000110000001000001 |
3 | 122112010221000021110212012111 |
4 | 132120210313010012001001 |
5 | 120003344213233104140 |
6 | 1152112515123455321 |
7 | 40101315644502553 |
oct | 3630446704060101 |
9 | 575127007425174 |
10 | 133630241300545 |
11 | 396402a3532170 |
12 | 12ba2529527541 |
13 | 597437c0c2462 |
14 | 24dda498374d3 |
15 | 106b068a4a7ea |
hex | 798937106041 |
133630241300545 has 32 divisors (see below), whose sum is σ = 176681037818880. Its totient is φ = 96215290080000.
The previous prime is 133630241300533. The next prime is 133630241300587. The reversal of 133630241300545 is 545003142036331.
It is not a de Polignac number, because 133630241300545 - 25 = 133630241300513 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133630241300498 and 133630241300507.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 65324976 + ... + 67339534.
It is an arithmetic number, because the mean of its divisors is an integer number (5521282431840).
Almost surely, 2133630241300545 is an apocalyptic number.
It is an amenable number.
133630241300545 is a deficient number, since it is larger than the sum of its proper divisors (43050796518335).
133630241300545 is a wasteful number, since it uses less digits than its factorization.
133630241300545 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2026617.
The product of its (nonzero) digits is 388800, while the sum is 40.
Adding to 133630241300545 its reverse (545003142036331), we get a palindrome (678633383336876).
The spelling of 133630241300545 in words is "one hundred thirty-three trillion, six hundred thirty billion, two hundred forty-one million, three hundred thousand, five hundred forty-five".
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