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1336542117 = 3445514039
BaseRepresentation
bin100111110101010…
…0000001110100101
310110010221101002220
41033222200032211
510214123321432
6340342422553
745056264151
oct11752401645
93403841086
101336542117
11626496969
12313731a59
13183b90931
14c9714061
157c50c72c
hex4faa03a5

1336542117 has 4 divisors (see below), whose sum is σ = 1782056160. Its totient is φ = 891028076.

The previous prime is 1336542107. The next prime is 1336542131. The reversal of 1336542117 is 7112456331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1336542117 - 214 = 1336525733 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1336542107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 222757017 + ... + 222757022.

It is an arithmetic number, because the mean of its divisors is an integer number (445514040).

Almost surely, 21336542117 is an apocalyptic number.

It is an amenable number.

1336542117 is a deficient number, since it is larger than the sum of its proper divisors (445514043).

1336542117 is an equidigital number, since it uses as much as digits as its factorization.

1336542117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 445514042.

The product of its digits is 15120, while the sum is 33.

The square root of 1336542117 is about 36558.7488434711. The cubic root of 1336542117 is about 1101.5246398122.

Adding to 1336542117 its reverse (7112456331), we get a palindrome (8448998448).

The spelling of 1336542117 in words is "one billion, three hundred thirty-six million, five hundred forty-two thousand, one hundred seventeen".

Divisors: 1 3 445514039 1336542117