133664255425103 has 4 divisors (see below), whose sum is σ = 143946121227048. Its totient is φ = 123382389623160.

The previous prime is 133664255425079. The next prime is 133664255425123. The reversal of 133664255425103 is 301524552466331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133664255425103 - 2¹⁰ = 133664255424079 is a prime.

It is a super-2 number, since 2×133664255425103² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133664255425123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5140932900953 + ... + 5140932900978.

It is an arithmetic number, because the mean of its divisors is an integer number (35986530306762).

Almost surely, 2^{133664255425103} is an apocalyptic number.

133664255425103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

133664255425103 is a deficient number, since it is larger than the sum of its proper divisors (10281865801945).

133664255425103 is a wasteful number, since it uses less digits than its factorization.

133664255425103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10281865801944.

The product of its (nonzero) digits is 7776000, while the sum is 50.

The spelling of 133664255425103 in words is "one hundred thirty-three trillion, six hundred sixty-four billion, two hundred fifty-five million, four hundred twenty-five thousand, one hundred three".