13383304703 has 4 divisors (see below), whose sum is σ = 13468548840. Its totient is φ = 13298060568.

The previous prime is 13383304687. The next prime is 13383304709. The reversal of 13383304703 is 30740338331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13383304703 - 2⁴ = 13383304687 is a prime.

It is a super-3 number, since 3×13383304703³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13383304709) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42621833 + ... + 42622146.

It is an arithmetic number, because the mean of its divisors is an integer number (3367137210).

Almost surely, 2^13383304703 is an apocalyptic number.

13383304703 is a deficient number, since it is larger than the sum of its proper divisors (85244137).

13383304703 is an equidigital number, since it uses as much as digits as its factorization.

13383304703 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 85244136.

The product of its (nonzero) digits is 54432, while the sum is 35.

The spelling of 13383304703 in words is "thirteen billion, three hundred eighty-three million, three hundred four thousand, seven hundred three".