Base | Representation |
---|---|
bin | 1100001011000001001111… |
… | …0011000100101110010111 |
3 | 1202101110000122210111102121 |
4 | 3002300103303010232113 |
5 | 3223233301231001020 |
6 | 44244134442120411 |
7 | 2550631242061660 |
oct | 302602363045627 |
9 | 52343018714377 |
10 | 13383450250135 |
11 | 429a986840069 |
12 | 16019764b0107 |
13 | 761091689b54 |
14 | 343a96230367 |
15 | 183203195baa |
hex | c2c13cc4b97 |
13383450250135 has 8 divisors (see below), whose sum is σ = 18354446057376. Its totient is φ = 9177223028640.
The previous prime is 13383450250097. The next prime is 13383450250171. The reversal of 13383450250135 is 53105205438331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13383450250135 - 219 = 13383449725847 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13383450250091 and 13383450250100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 191192146396 + ... + 191192146465.
It is an arithmetic number, because the mean of its divisors is an integer number (2294305757172).
Almost surely, 213383450250135 is an apocalyptic number.
13383450250135 is a deficient number, since it is larger than the sum of its proper divisors (4970995807241).
13383450250135 is an equidigital number, since it uses as much as digits as its factorization.
13383450250135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 382384292873.
The product of its (nonzero) digits is 648000, while the sum is 43.
Adding to 13383450250135 its reverse (53105205438331), we get a palindrome (66488655688466).
The spelling of 13383450250135 in words is "thirteen trillion, three hundred eighty-three billion, four hundred fifty million, two hundred fifty thousand, one hundred thirty-five".
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