133841811047 has 4 divisors (see below), whose sum is σ = 152962069776. Its totient is φ = 114721552320.

The previous prime is 133841811043. The next prime is 133841811079. The reversal of 133841811047 is 740118148331.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 740118148331 = 163 ⋅4540602137.

It is a cyclic number.

It is not a de Polignac number, because 133841811047 - 2² = 133841811043 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133841810995 and 133841811013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133841811041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9560129354 + ... + 9560129367.

It is an arithmetic number, because the mean of its divisors is an integer number (38240517444).

Almost surely, 2^133841811047 is an apocalyptic number.

133841811047 is a deficient number, since it is larger than the sum of its proper divisors (19120258729).

133841811047 is an equidigital number, since it uses as much as digits as its factorization.

133841811047 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19120258728.

The product of its (nonzero) digits is 64512, while the sum is 41.

Adding to 133841811047 its reverse (740118148331), we get a palindrome (873959959378).

The spelling of 133841811047 in words is "one hundred thirty-three billion, eight hundred forty-one million, eight hundred eleven thousand, forty-seven".