Base | Representation |
---|---|
bin | 111110010110000001… |
… | …0011111010110100111 |
3 | 110210120112011202211001 |
4 | 1330230002133112213 |
5 | 4143143001231031 |
6 | 141301021454131 |
7 | 12446512222033 |
oct | 1745402372647 |
9 | 423515152731 |
10 | 133882836391 |
11 | 51863409627 |
12 | 21b45111347 |
13 | c818453365 |
14 | 66a10411c3 |
15 | 3738b93861 |
hex | 1f2c09f5a7 |
133882836391 has 4 divisors (see below), whose sum is σ = 133895349000. Its totient is φ = 133870323784.
The previous prime is 133882836331. The next prime is 133882836407. The reversal of 133882836391 is 193638288331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 133882836391 - 215 = 133882803623 is a prime.
It is a super-2 number, since 2×1338828363912 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133882836331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6240241 + ... + 6261658.
It is an arithmetic number, because the mean of its divisors is an integer number (33473837250).
Almost surely, 2133882836391 is an apocalyptic number.
133882836391 is a deficient number, since it is larger than the sum of its proper divisors (12512609).
133882836391 is a wasteful number, since it uses less digits than its factorization.
133882836391 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12512608.
The product of its digits is 4478976, while the sum is 55.
The spelling of 133882836391 in words is "one hundred thirty-three billion, eight hundred eighty-two million, eight hundred thirty-six thousand, three hundred ninety-one".
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