Base | Representation |
---|---|
bin | 111110010110100100… |
… | …1011100000101101011 |
3 | 110210121211011200122102 |
4 | 1330231021130011223 |
5 | 4143212231411433 |
6 | 141302524244015 |
7 | 12450126264062 |
oct | 1745511340553 |
9 | 423554150572 |
10 | 133901435243 |
11 | 51872962184 |
12 | 21b4b3a060b |
13 | c81c265ab4 |
14 | 66a36c31d9 |
15 | 373a6194e8 |
hex | 1f2d25c16b |
133901435243 has 4 divisors (see below), whose sum is σ = 134878818120. Its totient is φ = 132924052368.
The previous prime is 133901435237. The next prime is 133901435251. The reversal of 133901435243 is 342534109331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 133901435243 - 28 = 133901434987 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 133901435197 and 133901435206.
It is not an unprimeable number, because it can be changed into a prime (133901435263) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 488691233 + ... + 488691506.
It is an arithmetic number, because the mean of its divisors is an integer number (33719704530).
Almost surely, 2133901435243 is an apocalyptic number.
133901435243 is a deficient number, since it is larger than the sum of its proper divisors (977382877).
133901435243 is an equidigital number, since it uses as much as digits as its factorization.
133901435243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 977382876.
The product of its (nonzero) digits is 116640, while the sum is 38.
The spelling of 133901435243 in words is "one hundred thirty-three billion, nine hundred one million, four hundred thirty-five thousand, two hundred forty-three".
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