Base | Representation |
---|---|
bin | 11000111100001111… |
… | …00111100100001001 |
3 | 1021120012001102101221 |
4 | 30132013213210021 |
5 | 204410343343213 |
6 | 10052410442041 |
7 | 652551644650 |
oct | 143607474411 |
9 | 37505042357 |
10 | 13390215433 |
11 | 5751478051 |
12 | 2718433321 |
13 | 13551987ca |
14 | 910504197 |
15 | 53583138d |
hex | 31e1e7909 |
13390215433 has 8 divisors (see below), whose sum is σ = 15351997568. Its totient is φ = 11440656864.
The previous prime is 13390215403. The next prime is 13390215481. The reversal of 13390215433 is 33451209331.
13390215433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13390215433 - 225 = 13356661001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13390215403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3053541 + ... + 3057922.
It is an arithmetic number, because the mean of its divisors is an integer number (1918999696).
Almost surely, 213390215433 is an apocalyptic number.
It is an amenable number.
13390215433 is a deficient number, since it is larger than the sum of its proper divisors (1961782135).
13390215433 is an equidigital number, since it uses as much as digits as its factorization.
13390215433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6111783.
The product of its (nonzero) digits is 29160, while the sum is 34.
The spelling of 13390215433 in words is "thirteen billion, three hundred ninety million, two hundred fifteen thousand, four hundred thirty-three".
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