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1339140503 = 6134616343
BaseRepresentation
bin100111111010001…
…1010100110010111
310110022211101102102
41033310122212113
510220304444003
6340514232315
745120335501
oct11764324627
93408741372
101339140503
11627a01098
1231458569b
1318459053c
14c9bccd71
157c872588
hex4fd1a997

1339140503 has 8 divisors (see below), whose sum is σ = 1361701536. Its totient is φ = 1316599200.

The previous prime is 1339140499. The next prime is 1339140553. The reversal of 1339140503 is 3050419331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1339140503 - 22 = 1339140499 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1339140553) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 207950 + ... + 214292.

It is an arithmetic number, because the mean of its divisors is an integer number (170212692).

Almost surely, 21339140503 is an apocalyptic number.

1339140503 is a deficient number, since it is larger than the sum of its proper divisors (22561033).

1339140503 is an equidigital number, since it uses as much as digits as its factorization.

1339140503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9865.

The product of its (nonzero) digits is 4860, while the sum is 29.

The square root of 1339140503 is about 36594.2687179290. The cubic root of 1339140503 is about 1102.2380063832.

Adding to 1339140503 its reverse (3050419331), we get a palindrome (4389559834).

The spelling of 1339140503 in words is "one billion, three hundred thirty-nine million, one hundred forty thousand, five hundred three".

Divisors: 1 61 3461 6343 211121 386923 21953123 1339140503