Base | Representation |
---|---|
bin | 111110011000100011… |
… | …0011001110011111111 |
3 | 110210210102221202010110 |
4 | 1330301012121303333 |
5 | 4143331220421401 |
6 | 141313253441103 |
7 | 12451563033543 |
oct | 1746106316377 |
9 | 423712852113 |
10 | 133967748351 |
11 | 518a73351a8 |
12 | 21b69640193 |
13 | c82cc13418 |
14 | 66ac425a23 |
15 | 37413679d6 |
hex | 1f31199cff |
133967748351 has 8 divisors (see below), whose sum is σ = 179011136304. Its totient is φ = 89118096320.
The previous prime is 133967748347. The next prime is 133967748403. The reversal of 133967748351 is 153847769331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 133967748351 - 22 = 133967748347 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133967748291 and 133967748300.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133967748151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 48432366 + ... + 48435131.
It is an arithmetic number, because the mean of its divisors is an integer number (22376392038).
Almost surely, 2133967748351 is an apocalyptic number.
133967748351 is a deficient number, since it is larger than the sum of its proper divisors (45043387953).
133967748351 is an equidigital number, since it uses as much as digits as its factorization.
133967748351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 96867961.
The product of its digits is 11430720, while the sum is 57.
The spelling of 133967748351 in words is "one hundred thirty-three billion, nine hundred sixty-seven million, seven hundred forty-eight thousand, three hundred fifty-one".
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