Base | Representation |
---|---|
bin | 1100001011111011101001… |
… | …1101010011000101101010 |
3 | 1202102221111111100020220011 |
4 | 3002332322131103011222 |
5 | 3224012410044120022 |
6 | 44255250444122134 |
7 | 2552024651221663 |
oct | 302767235230552 |
9 | 52387444306804 |
10 | 13399131238762 |
11 | 42a65a32a69a5 |
12 | 1604a11b3634a |
13 | 7626c0319b49 |
14 | 344742a8036a |
15 | 18381eb74977 |
hex | c2fba75316a |
13399131238762 has 4 divisors (see below), whose sum is σ = 20098696858146. Its totient is φ = 6699565619380.
The previous prime is 13399131238741. The next prime is 13399131238769. The reversal of 13399131238762 is 26783213199331.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 11483091146241 + 1916040092521 = 3388671^2 + 1384211^2 .
It is a junction number, because it is equal to n+sod(n) for n = 13399131238697 and 13399131238706.
It is not an unprimeable number, because it can be changed into a prime (13399131238769) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3349782809689 + ... + 3349782809692.
Almost surely, 213399131238762 is an apocalyptic number.
13399131238762 is a deficient number, since it is larger than the sum of its proper divisors (6699565619384).
13399131238762 is an equidigital number, since it uses as much as digits as its factorization.
13399131238762 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6699565619383.
The product of its digits is 8817984, while the sum is 58.
The spelling of 13399131238762 in words is "thirteen trillion, three hundred ninety-nine billion, one hundred thirty-one million, two hundred thirty-eight thousand, seven hundred sixty-two".
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