1340000214431 has 4 divisors (see below), whose sum is σ = 1349781238032. Its totient is φ = 1330219190832.

The previous prime is 1340000214341. The next prime is 1340000214437. The reversal of 1340000214431 is 1344120000431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1340000214431 - 2¹⁰ = 1340000213407 is a prime.

It is a super-2 number, since 2×1340000214431² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1340000214397 and 1340000214406.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340000214437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4890511595 + ... + 4890511868.

It is an arithmetic number, because the mean of its divisors is an integer number (337445309508).

Almost surely, 2^{1340000214431} is an apocalyptic number.

1340000214431 is a deficient number, since it is larger than the sum of its proper divisors (9781023601).

1340000214431 is an equidigital number, since it uses as much as digits as its factorization.

1340000214431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9781023600.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1340000214431 its reverse (1344120000431), we get a palindrome (2684120214862).

The spelling of 1340000214431 in words is "one trillion, three hundred forty billion, two hundred fourteen thousand, four hundred thirty-one".