1340001225541 has 4 divisors (see below), whose sum is σ = 1461819518784. Its totient is φ = 1218182932300.

The previous prime is 1340001225539. The next prime is 1340001225547. The reversal of 1340001225541 is 1455221000431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1340001225541 - 2¹ = 1340001225539 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340001225547) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60909146605 + ... + 60909146626.

It is an arithmetic number, because the mean of its divisors is an integer number (365454879696).

Almost surely, 2^{1340001225541} is an apocalyptic number.

1340001225541 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1340001225541 is a deficient number, since it is larger than the sum of its proper divisors (121818293243).

1340001225541 is a wasteful number, since it uses less digits than its factorization.

1340001225541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 121818293242.

The product of its (nonzero) digits is 4800, while the sum is 28.

Adding to 1340001225541 its reverse (1455221000431), we get a palindrome (2795222225972).

The spelling of 1340001225541 in words is "one trillion, three hundred forty billion, one million, two hundred twenty-five thousand, five hundred forty-one".