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13400025445 = 512792095391
BaseRepresentation
bin11000111101011010…
…00010100101100101
31021120212111211012201
430132231002211211
5204420401303240
610053401014501
7653031223402
oct143655024545
937525454181
1013400025445
115756a684a4
12271b784431
131357221a51
149119392a9
1553661cd9a
hex31eb42965

13400025445 has 8 divisors (see below), whose sum is σ = 16092610560. Its totient is φ = 10711633680.

The previous prime is 13400025439. The next prime is 13400025491. The reversal of 13400025445 is 54452000431.

13400025445 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13400025445 - 23 = 13400025437 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1041301 + ... + 1054090.

It is an arithmetic number, because the mean of its divisors is an integer number (2011576320).

Almost surely, 213400025445 is an apocalyptic number.

It is an amenable number.

13400025445 is a deficient number, since it is larger than the sum of its proper divisors (2692585115).

13400025445 is a wasteful number, since it uses less digits than its factorization.

13400025445 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2096675.

The product of its (nonzero) digits is 9600, while the sum is 28.

Adding to 13400025445 its reverse (54452000431), we get a palindrome (67852025876).

The spelling of 13400025445 in words is "thirteen billion, four hundred million, twenty-five thousand, four hundred forty-five".

Divisors: 1 5 1279 6395 2095391 10476955 2680005089 13400025445