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13400045336042 = 27194366516451
BaseRepresentation
bin1100001011111111000011…
…1100010011010111101010
31202110000212012101012121222
43002333300330103113222
53224021243101223132
644255521300302042
72552056421013431
oct302776074232752
952400765335558
1013400045336042
1142a6a222877a2
1216050280a1922
1376280780b001
143447cc22a118
15183875038412
hexc2ff0f135ea

13400045336042 has 8 divisors (see below), whose sum is σ = 20383167553632. Its totient is φ = 6605656151500.

The previous prime is 13400045335993. The next prime is 13400045336047. The reversal of 13400045336042 is 24063354000431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×134000453360422 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13400045335993 and 13400045336011.

It is not an unprimeable number, because it can be changed into a prime (13400045336047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47183258084 + ... + 47183258367.

It is an arithmetic number, because the mean of its divisors is an integer number (2547895944204).

Almost surely, 213400045336042 is an apocalyptic number.

13400045336042 is a deficient number, since it is larger than the sum of its proper divisors (6983122217590).

13400045336042 is an equidigital number, since it uses as much as digits as its factorization.

13400045336042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 94366516524.

The product of its (nonzero) digits is 103680, while the sum is 35.

Adding to 13400045336042 its reverse (24063354000431), we get a palindrome (37463399336473).

The spelling of 13400045336042 in words is "thirteen trillion, four hundred billion, forty-five million, three hundred thirty-six thousand, forty-two".

Divisors: 1 2 71 142 94366516451 188733032902 6700022668021 13400045336042