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13400098359562 = 224127801033941
BaseRepresentation
bin1100001011111111010000…
…0110100100100100001010
31202110000222220011002020001
43002333310012210210022
53224021400140001222
644255530432553214
72552060633503105
oct302776406444412
952400886132201
1013400098359562
1142a6a4a203092
1216050419b280a
137628157b4685
143447d52ad73c
15183879a0de27
hexc2ff41a490a

13400098359562 has 8 divisors (see below), whose sum is σ = 20183550641892. Its totient is φ = 6672248145600.

The previous prime is 13400098359533. The next prime is 13400098359569. The reversal of 13400098359562 is 26595389000431.

It can be written as a sum of positive squares in 2 ways, for example, as 13168690219161 + 231408140401 = 3628869^2 + 481049^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×134000983595623 (a number of 40 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (13400098359569) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13900516489 + ... + 13900517452.

Almost surely, 213400098359562 is an apocalyptic number.

13400098359562 is a deficient number, since it is larger than the sum of its proper divisors (6783452282330).

13400098359562 is a wasteful number, since it uses less digits than its factorization.

13400098359562 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27801034184.

The product of its (nonzero) digits is 6998400, while the sum is 55.

The spelling of 13400098359562 in words is "thirteen trillion, four hundred billion, ninety-eight million, three hundred fifty-nine thousand, five hundred sixty-two".

Divisors: 1 2 241 482 27801033941 55602067882 6700049179781 13400098359562