Base | Representation |
---|---|
bin | 11000111101011100… |
… | …00110101001110011 |
3 | 1021120220000222122120 |
4 | 30132232012221303 |
5 | 204420434213433 |
6 | 10053411005323 |
7 | 653033464254 |
oct | 143656065163 |
9 | 37526028576 |
10 | 13400304243 |
11 | 5757138a07 |
12 | 271b899843 |
13 | 13572bb911 |
14 | 9119acb2b |
15 | 5366757b3 |
hex | 31eb86a73 |
13400304243 has 4 divisors (see below), whose sum is σ = 17867072328. Its totient is φ = 8933536160.
The previous prime is 13400304241. The next prime is 13400304263. The reversal of 13400304243 is 34240300431.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34240300431 = 3 ⋅11413433477.
It is a cyclic number.
It is not a de Polignac number, because 13400304243 - 21 = 13400304241 is a prime.
It is a super-3 number, since 3×134003042433 (a number of 31 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (13400304241) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2233384038 + ... + 2233384043.
It is an arithmetic number, because the mean of its divisors is an integer number (4466768082).
Almost surely, 213400304243 is an apocalyptic number.
13400304243 is a deficient number, since it is larger than the sum of its proper divisors (4466768085).
13400304243 is an equidigital number, since it uses as much as digits as its factorization.
13400304243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4466768084.
The product of its (nonzero) digits is 3456, while the sum is 24.
Adding to 13400304243 its reverse (34240300431), we get a palindrome (47640604674).
The spelling of 13400304243 in words is "thirteen billion, four hundred million, three hundred four thousand, two hundred forty-three".
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