Base | Representation |
---|---|
bin | 11000111101011100… |
… | …10100101000101010 |
3 | 1021120220010220012201 |
4 | 30132232110220222 |
5 | 204420443032024 |
6 | 10053412130414 |
7 | 653034123241 |
oct | 143656245052 |
9 | 37526126181 |
10 | 13400361514 |
11 | 5757177a41 |
12 | 271b906a0a |
13 | 135730b9c7 |
14 | 9119c5958 |
15 | 536687744 |
hex | 31eb94a2a |
13400361514 has 4 divisors (see below), whose sum is σ = 20100542274. Its totient is φ = 6700180756.
The previous prime is 13400361511. The next prime is 13400361517. The reversal of 13400361514 is 41516300431.
13400361514 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (13400361511) and next prime (13400361517).
It can be written as a sum of positive squares in only one way, i.e., 13067919225 + 332442289 = 114315^2 + 18233^2 .
It is not an unprimeable number, because it can be changed into a prime (13400361511) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3350090377 + ... + 3350090380.
Almost surely, 213400361514 is an apocalyptic number.
13400361514 is a deficient number, since it is larger than the sum of its proper divisors (6700180760).
13400361514 is an equidigital number, since it uses as much as digits as its factorization.
13400361514 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6700180759.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 13400361514 its reverse (41516300431), we get a palindrome (54916661945).
The spelling of 13400361514 in words is "thirteen billion, four hundred million, three hundred sixty-one thousand, five hundred fourteen".
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