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13400442510153 = 389173643451181
BaseRepresentation
bin1100001100000000100010…
…0111011001101101001001
31202110001212212201202002020
43003000020213121231021
53224023101240311103
644300024525155053
72552102312645436
oct303001047315511
952401785652066
1013400442510153
1142a71064a2566
1216051190bba89
1376286bba028a
14344828c96b8d
15183899d3e753
hexc30089d9b49

13400442510153 has 32 divisors (see below), whose sum is σ = 18200754069120. Its totient is φ = 8768513656320.

The previous prime is 13400442510151. The next prime is 13400442510163. The reversal of 13400442510153 is 35101524400431.

It is not a de Polignac number, because 13400442510153 - 21 = 13400442510151 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13400442510151) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 29475223 + ... + 29926403.

It is an arithmetic number, because the mean of its divisors is an integer number (568773564660).

Almost surely, 213400442510153 is an apocalyptic number.

It is an amenable number.

13400442510153 is a deficient number, since it is larger than the sum of its proper divisors (4800311558967).

13400442510153 is a wasteful number, since it uses less digits than its factorization.

13400442510153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 452089.

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 13400442510153 its reverse (35101524400431), we get a palindrome (48501966910584).

The spelling of 13400442510153 in words is "thirteen trillion, four hundred billion, four hundred forty-two million, five hundred ten thousand, one hundred fifty-three".

Divisors: 1 3 89 173 267 519 643 1929 15397 46191 57227 111239 171681 333717 451181 1353543 9900271 29700813 40155109 78054313 120465327 234162939 290109383 870328149 6946833857 20840501571 25819735087 50188923259 77459205261 150566769777 4466814170051 13400442510153