Base | Representation |
---|---|
bin | 1100001100000000100010… |
… | …0111011001101101001001 |
3 | 1202110001212212201202002020 |
4 | 3003000020213121231021 |
5 | 3224023101240311103 |
6 | 44300024525155053 |
7 | 2552102312645436 |
oct | 303001047315511 |
9 | 52401785652066 |
10 | 13400442510153 |
11 | 42a71064a2566 |
12 | 16051190bba89 |
13 | 76286bba028a |
14 | 344828c96b8d |
15 | 183899d3e753 |
hex | c30089d9b49 |
13400442510153 has 32 divisors (see below), whose sum is σ = 18200754069120. Its totient is φ = 8768513656320.
The previous prime is 13400442510151. The next prime is 13400442510163. The reversal of 13400442510153 is 35101524400431.
It is not a de Polignac number, because 13400442510153 - 21 = 13400442510151 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13400442510151) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 29475223 + ... + 29926403.
It is an arithmetic number, because the mean of its divisors is an integer number (568773564660).
Almost surely, 213400442510153 is an apocalyptic number.
It is an amenable number.
13400442510153 is a deficient number, since it is larger than the sum of its proper divisors (4800311558967).
13400442510153 is a wasteful number, since it uses less digits than its factorization.
13400442510153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 452089.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 13400442510153 its reverse (35101524400431), we get a palindrome (48501966910584).
The spelling of 13400442510153 in words is "thirteen trillion, four hundred billion, four hundred forty-two million, five hundred ten thousand, one hundred fifty-three".
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