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13400525345341 = 401158812104261
BaseRepresentation
bin1100001100000000110110…
…0011011001001000111101
31202110002002122121012121011
43003000031203121020331
53224023233442022331
644300041044435221
72552104340020441
oct303001543311075
952402078535534
1013400525345341
1142a714922a8a2
1216051409a8b11
137628830b3c94
14344835c9a821
151838a22533b1
hexc300d8d923d

13400525345341 has 8 divisors (see below), whose sum is σ = 13434795411768. Its totient is φ = 13366259520000.

The previous prime is 13400525345329. The next prime is 13400525345353. The reversal of 13400525345341 is 14354352500431.

It is an interprime number because it is at equal distance from previous prime (13400525345329) and next prime (13400525345353).

It can be written as a sum of positive squares in 4 ways, for example, as 7360993003225 + 6039532342116 = 2713115^2 + 2457546^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13400525345341 - 213 = 13400525337149 is a prime.

It is a super-2 number, since 2×134005253453412 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13400525345294 and 13400525345303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13400525345381) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5316151 + ... + 7420411.

It is an arithmetic number, because the mean of its divisors is an integer number (1679349426471).

Almost surely, 213400525345341 is an apocalyptic number.

It is an amenable number.

13400525345341 is a deficient number, since it is larger than the sum of its proper divisors (34270066427).

13400525345341 is a wasteful number, since it uses less digits than its factorization.

13400525345341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2120543.

The product of its (nonzero) digits is 432000, while the sum is 40.

Adding to 13400525345341 its reverse (14354352500431), we get a palindrome (27754877845772).

The spelling of 13400525345341 in words is "thirteen trillion, four hundred billion, five hundred twenty-five million, three hundred forty-five thousand, three hundred forty-one".

Divisors: 1 401 15881 2104261 6368281 843808661 33417768941 13400525345341