13400535425234 has 4 divisors (see below), whose sum is σ = 20100803137854. Its totient is φ = 6700267712616.

The previous prime is 13400535425213. The next prime is 13400535425243. The reversal of 13400535425234 is 43252453500431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 9169298767225 + 4231236658009 = 3028085^2 + 2056997^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13400535425191 and 13400535425200.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3350133856307 + ... + 3350133856310.

Almost surely, 2^{13400535425234} is an apocalyptic number.

13400535425234 is a deficient number, since it is larger than the sum of its proper divisors (6700267712620).

13400535425234 is an equidigital number, since it uses as much as digits as its factorization.

13400535425234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6700267712619.

The product of its (nonzero) digits is 864000, while the sum is 41.

Adding to 13400535425234 its reverse (43252453500431), we get a palindrome (56652988925665).

The spelling of 13400535425234 in words is "thirteen trillion, four hundred billion, five hundred thirty-five million, four hundred twenty-five thousand, two hundred thirty-four".