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1340070086143 = 11311859027311
BaseRepresentation
bin10011100000000010011…
…001101100010111111111
311202002221210021201211201
4103200002121230113333
5133423430420224033
62503341504400331
7165550120535065
oct23400231542777
94662853251751
101340070086143
1147735869aa68
1219786a9160a7
13994a2848799
1448c0719c035
1524cd1b5347d
hex1380266c5ff

1340070086143 has 4 divisors (see below), whose sum is σ = 1351929113568. Its totient is φ = 1328211058720.

The previous prime is 1340070086137. The next prime is 1340070086153. The reversal of 1340070086143 is 3416800700431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1340070086143 - 217 = 1340069955071 is a prime.

It is a super-3 number, since 3×13400700861433 (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340070086153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5929513543 + ... + 5929513768.

It is an arithmetic number, because the mean of its divisors is an integer number (337982278392).

Almost surely, 21340070086143 is an apocalyptic number.

1340070086143 is a deficient number, since it is larger than the sum of its proper divisors (11859027425).

1340070086143 is a wasteful number, since it uses less digits than its factorization.

1340070086143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11859027424.

The product of its (nonzero) digits is 48384, while the sum is 37.

Adding to 1340070086143 its reverse (3416800700431), we get a palindrome (4756870786574).

The spelling of 1340070086143 in words is "one trillion, three hundred forty billion, seventy million, eighty-six thousand, one hundred forty-three".

Divisors: 1 113 11859027311 1340070086143