Base | Representation |
---|---|
bin | 10011100000000010011… |
… | …001101100010111111111 |
3 | 11202002221210021201211201 |
4 | 103200002121230113333 |
5 | 133423430420224033 |
6 | 2503341504400331 |
7 | 165550120535065 |
oct | 23400231542777 |
9 | 4662853251751 |
10 | 1340070086143 |
11 | 47735869aa68 |
12 | 19786a9160a7 |
13 | 994a2848799 |
14 | 48c0719c035 |
15 | 24cd1b5347d |
hex | 1380266c5ff |
1340070086143 has 4 divisors (see below), whose sum is σ = 1351929113568. Its totient is φ = 1328211058720.
The previous prime is 1340070086137. The next prime is 1340070086153. The reversal of 1340070086143 is 3416800700431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1340070086143 - 217 = 1340069955071 is a prime.
It is a super-3 number, since 3×13400700861433 (a number of 37 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1340070086153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5929513543 + ... + 5929513768.
It is an arithmetic number, because the mean of its divisors is an integer number (337982278392).
Almost surely, 21340070086143 is an apocalyptic number.
1340070086143 is a deficient number, since it is larger than the sum of its proper divisors (11859027425).
1340070086143 is a wasteful number, since it uses less digits than its factorization.
1340070086143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11859027424.
The product of its (nonzero) digits is 48384, while the sum is 37.
Adding to 1340070086143 its reverse (3416800700431), we get a palindrome (4756870786574).
The spelling of 1340070086143 in words is "one trillion, three hundred forty billion, seventy million, eighty-six thousand, one hundred forty-three".
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