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1340100133 = 36717532083
BaseRepresentation
bin100111111100000…
…0100111000100101
310110101122010210021
41033320010320211
510221031201013
6340550555141
745131443321
oct11770047045
93411563707
101340100133
116284a7079
12314968ab1
13184838278
14c9d9c981
157c9b1a8d
hex4fe04e25

1340100133 has 8 divisors (see below), whose sum is σ = 1345163648. Its totient is φ = 1335045024.

The previous prime is 1340100127. The next prime is 1340100169. The reversal of 1340100133 is 3310010431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1340100133 - 25 = 1340100101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340100103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 642310 + ... + 644392.

It is an arithmetic number, because the mean of its divisors is an integer number (168145456).

Almost surely, 21340100133 is an apocalyptic number.

It is an amenable number.

1340100133 is a deficient number, since it is larger than the sum of its proper divisors (5063515).

1340100133 is a wasteful number, since it uses less digits than its factorization.

1340100133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4203.

The product of its (nonzero) digits is 108, while the sum is 16.

The square root of 1340100133 is about 36607.3781224496. The cubic root of 1340100133 is about 1102.5012319613.

Adding to 1340100133 its reverse (3310010431), we get a palindrome (4650110564).

The spelling of 1340100133 in words is "one billion, three hundred forty million, one hundred thousand, one hundred thirty-three".

Divisors: 1 367 1753 2083 643351 764461 3651499 1340100133