Base | Representation |
---|---|
bin | 1100001100000010110000… |
… | …1111000010011101001001 |
3 | 1202110010102112012121200120 |
4 | 3003000230033002131021 |
5 | 3224030312231300431 |
6 | 44300204113453453 |
7 | 2552123160261360 |
oct | 303005417023511 |
9 | 52403375177616 |
10 | 13401040103241 |
11 | 42a739285704a |
12 | 1605265271289 |
13 | 76293593545b |
14 | 3448843b47d7 |
15 | 1838d2534196 |
hex | c302c3c2749 |
13401040103241 has 8 divisors (see below), whose sum is σ = 20420632538304. Its totient is φ = 7657737201840.
The previous prime is 13401040103233. The next prime is 13401040103293. The reversal of 13401040103241 is 14230104010431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13401040103241 - 23 = 13401040103233 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13401040104241) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 319072383390 + ... + 319072383431.
It is an arithmetic number, because the mean of its divisors is an integer number (2552579067288).
Almost surely, 213401040103241 is an apocalyptic number.
It is an amenable number.
13401040103241 is a deficient number, since it is larger than the sum of its proper divisors (7019592435063).
13401040103241 is an equidigital number, since it uses as much as digits as its factorization.
13401040103241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 638144766831.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 13401040103241 its reverse (14230104010431), we get a palindrome (27631144113672).
The spelling of 13401040103241 in words is "thirteen trillion, four hundred one billion, forty million, one hundred three thousand, two hundred forty-one".
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