Base | Representation |
---|---|
bin | 1100001100000011000010… |
… | …0110010001000000001011 |
3 | 1202110010121121221110010210 |
4 | 3003000300212101000023 |
5 | 3224030440001113003 |
6 | 44300215250412203 |
7 | 2552125036404051 |
oct | 303006046210013 |
9 | 52403547843123 |
10 | 13401113301003 |
11 | 42a742010166a |
12 | 1605285891063 |
13 | 762947b5363c |
14 | 34488ddca1d1 |
15 | 1838d8b92503 |
hex | c303099100b |
13401113301003 has 32 divisors (see below), whose sum is σ = 18541240200000. Its totient is φ = 8599439826432.
The previous prime is 13401113301001. The next prime is 13401113301007. The reversal of 13401113301003 is 30010331110431.
It is not a de Polignac number, because 13401113301003 - 21 = 13401113301001 is a prime.
It is a super-3 number, since 3×134011133010033 (a number of 40 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (13401113301001) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 149007013 + ... + 149096921.
It is an arithmetic number, because the mean of its divisors is an integer number (579413756250).
Almost surely, 213401113301003 is an apocalyptic number.
13401113301003 is a deficient number, since it is larger than the sum of its proper divisors (5140126898997).
13401113301003 is a wasteful number, since it uses less digits than its factorization.
13401113301003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 95199.
The product of its (nonzero) digits is 324, while the sum is 21.
Adding to 13401113301003 its reverse (30010331110431), we get a palindrome (43411444411434).
The spelling of 13401113301003 in words is "thirteen trillion, four hundred one billion, one hundred thirteen million, three hundred one thousand, three".
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