13401134202413 has 4 divisors (see below), whose sum is σ = 13401152944800. Its totient is φ = 13401115460028.

The previous prime is 13401134202371. The next prime is 13401134202427. The reversal of 13401134202413 is 31420243110431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13401134202413 - 2²⁴ = 13401117425197 is a prime.

It is a super-2 number, since 2×13401134202413² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13401134202913) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8254295 + ... + 9743492.

It is an arithmetic number, because the mean of its divisors is an integer number (3350288236200).

Almost surely, 2^{13401134202413} is an apocalyptic number.

It is an amenable number.

13401134202413 is a deficient number, since it is larger than the sum of its proper divisors (18742387).

13401134202413 is an equidigital number, since it uses as much as digits as its factorization.

13401134202413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18742386.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 13401134202413 its reverse (31420243110431), we get a palindrome (44821377312844).

The spelling of 13401134202413 in words is "thirteen trillion, four hundred one billion, one hundred thirty-four million, two hundred two thousand, four hundred thirteen".