13401203424023 has 4 divisors (see below), whose sum is σ = 13406498252088. Its totient is φ = 13395908595960.

The previous prime is 13401203423987. The next prime is 13401203424047. The reversal of 13401203424023 is 32042430210431.

13401203424023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13401203424023 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13401203424053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2647410236 + ... + 2647415297.

It is an arithmetic number, because the mean of its divisors is an integer number (3351624563022).

Almost surely, 2^{13401203424023} is an apocalyptic number.

13401203424023 is a deficient number, since it is larger than the sum of its proper divisors (5294828065).

13401203424023 is an equidigital number, since it uses as much as digits as its factorization.

13401203424023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5294828064.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 13401203424023 its reverse (32042430210431), we get a palindrome (45443633634454).

The spelling of 13401203424023 in words is "thirteen trillion, four hundred one billion, two hundred three million, four hundred twenty-four thousand, twenty-three".