13401204213 has 4 divisors (see below), whose sum is σ = 17868272288. Its totient is φ = 8934136140.

The previous prime is 13401204139. The next prime is 13401204221. The reversal of 13401204213 is 31240210431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13401204213 - 2²¹ = 13399107061 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 13401204213.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13401204913) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2233534033 + ... + 2233534038.

It is an arithmetic number, because the mean of its divisors is an integer number (4467068072).

Almost surely, 2^13401204213 is an apocalyptic number.

It is an amenable number.

13401204213 is a deficient number, since it is larger than the sum of its proper divisors (4467068075).

13401204213 is an equidigital number, since it uses as much as digits as its factorization.

13401204213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4467068074.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 13401204213 its reverse (31240210431), we get a palindrome (44641414644).

The spelling of 13401204213 in words is "thirteen billion, four hundred one million, two hundred four thousand, two hundred thirteen".